Follow these steps:
In the picture below, the vector has a magnitude of 60 and its direction is 73° above the positive x axis.
Express the vector's coordinates below as ordered pairs in simplest radical form.
$$ \text{X Coordinate} \\ = 2 \cdot { \bf cos}(30^{\circ}) \\ = 2 \cdot \frac{\sqrt{3}}{2}= \red{ \sqrt{3}} $$
$$ \text{Y Coordinate} \\ = 2 \cdot { \bf sin}(30^{\circ}) \\ = 2 \cdot \frac{1}{2}= \red 2 $$
$$ (\sqrt{3}, 2) $$
Express the vectors coordinates below as ordered pairs in simplest radical form.
This was kind of a trick question in that you must recognize that the 60° angle is the same as the prior problem's angle( i.e. it is 30° from the x-axis ).
$$ \text{X Coordinate} \\ = 2 \cdot { \bf sin}(60^{\circ}) \\ = 2 \cdot \frac{\sqrt{3}}{2}= \red{ \sqrt{3}} $$
$$ \text{Y Coordinate} \\ = 2 \cdot { \bf sin}(30^{\circ}) \\ = 2 \cdot \frac{1}{2}= \red 2 $$
$$ (\sqrt{3}, 2) $$
